7[2-(3+4x)]-4x=-9+2(1-16x)

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Solution for 7[2-(3+4x)]-4x=-9+2(1-16x) equation: 


Simplifying
7[2 + -1(3 + 4x)] + -4x = -9 + 2(1 + -16x)
7[2 + (3 * -1 + 4x * -1)] + -4x = -9 + 2(1 + -16x)
7[2 + (-3 + -4x)] + -4x = -9 + 2(1 + -16x)

Combine like terms: 2 + -3 = -1
7[-1 + -4x] + -4x = -9 + 2(1 + -16x)
[-1 * 7 + -4x * 7] + -4x = -9 + 2(1 + -16x)
[-7 + -28x] + -4x = -9 + 2(1 + -16x)

Combine like terms: -28x + -4x = -32x
-7 + -32x = -9 + 2(1 + -16x)
-7 + -32x = -9 + (1 * 2 + -16x * 2)
-7 + -32x = -9 + (2 + -32x)

Combine like terms: -9 + 2 = -7
-7 + -32x = -7 + -32x

Add '7' to each side of the equation.
-7 + 7 + -32x = -7 + 7 + -32x

Combine like terms: -7 + 7 = 0
0 + -32x = -7 + 7 + -32x
-32x = -7 + 7 + -32x

Combine like terms: -7 + 7 = 0
-32x = 0 + -32x
-32x = -32x

Add '32x' to each side of the equation.
-32x + 32x = -32x + 32x

Combine like terms: -32x + 32x = 0
0 = -32x + 32x

Combine like terms: -32x + 32x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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